4[3(x+3)+x+4]-3(4x+16)=0

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Solution for 4[3(x+3)+x+4]-3(4x+16)=0 equation:


Simplifying
4[3(x + 3) + x + 4] + -3(4x + 16) = 0

Reorder the terms:
4[3(3 + x) + x + 4] + -3(4x + 16) = 0
4[(3 * 3 + x * 3) + x + 4] + -3(4x + 16) = 0
4[(9 + 3x) + x + 4] + -3(4x + 16) = 0

Reorder the terms:
4[9 + 4 + 3x + x] + -3(4x + 16) = 0

Combine like terms: 9 + 4 = 13
4[13 + 3x + x] + -3(4x + 16) = 0

Combine like terms: 3x + x = 4x
4[13 + 4x] + -3(4x + 16) = 0
[13 * 4 + 4x * 4] + -3(4x + 16) = 0
[52 + 16x] + -3(4x + 16) = 0

Reorder the terms:
52 + 16x + -3(16 + 4x) = 0
52 + 16x + (16 * -3 + 4x * -3) = 0
52 + 16x + (-48 + -12x) = 0

Reorder the terms:
52 + -48 + 16x + -12x = 0

Combine like terms: 52 + -48 = 4
4 + 16x + -12x = 0

Combine like terms: 16x + -12x = 4x
4 + 4x = 0

Solving
4 + 4x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 4x = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 4x = 0 + -4
4x = 0 + -4

Combine like terms: 0 + -4 = -4
4x = -4

Divide each side by '4'.
x = -1

Simplifying
x = -1

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